#include<stdio.h>
  2 
  3 int year_loap(int n);//判断形参n是否为润年。返回值1或2.
  4 int year_num(int yy,int mm,int dd);//计算当前月份，为这一年的第几天。
  5 
  6 int main()
  7 {
  8         int year = 2012, month = 5, day =23;
  9         int x = 0;
 10 
 11         x = year_num(year,month,day);
 12         printf("%d\n",x);
 13 }
 14 
 15 
 16 /*int year_num(int yy,int mm,int dd)
 17 {
 18         int sum = 0;
 19 
 20         switch(mm)
 21         {
 22                 case 1:sum = dd;break;
 23                 case 2:sum = 31+dd;break;
 24                 case 3:sum = 60+dd;break;
 25                 case 4:sum = 91+dd;break;
 26                 case 5:sum =121+dd;break;
 27                 case 6:sum =152+dd;break;
 28                 case 7:sum =182+dd;break;
 29                 case 8:sum =213+dd;break;
 30                 case 9:sum =244+dd;break;
 31                 case 10:sum =274+dd;break;
 32                 case 11:sum =305+dd;break;
 33                 case 12:sum =335+dd;break;
 34         }
 35         if(1 == year_loap(yy))
 36         return sum;
 37         else return sum-1;
 38 }*/
 int year_loap(int n)
 42 {
 43         int i = 0;
 44         if(0 == n%4)
 45         {
 46                 if(0 == n%100)
 47                 {
 48                         if(0 == n%400)
 49                         {
 50                                 return 1;
 51                         }
 52                         else return 2;
 53                 }
 54                 else return 1;
 55         }
 56         else return 2;
 57 }
 58 int year_num(int yy,int mm,int dd)
 59 {
 60         int a[] = {31,28,31,30,31,30,31,31,30,31,30,31};
 61         int i = 0,sum = 0;
 62 
 63         if(mm>2)
 64         {
 65                 for(i = 0;i<mm-1; i++)
 66                 {
 67                         sum = sum+a[i];
 68                 }
 69                 sum = sum+dd;
 70         }
 71         else sum = 31+dd;
 72         if(1 == year_loap(yy))
 73         return sum+1;
 74         else return sum;
 75 }